How many possibilities are there in a 10-digit number?

How many possibilities are there in a 10-digit number?

If repetition is allowed, then the number of permutations of 10 digits is 10,000,000,000.

How many combinations are there with 10 numbers without repetition?

Well there a lot of 10-digit numbers . The first place can’t have the face value 0,so only 9 number can be put in it. The remaining 9 places can have 10 in each place. So there are 9*10^9 = 9,000,000,000 10-Digit numbers.

How many different ten digit numbers can be written with the digits 0 to 9?

So there are 9*10^9 = 9,000,000,000 10-Digit numbers.

How many telephone numbers are possible?

Each area code has 792 prefixes or “NXX” codes. Each NXX has 10,000 possible numbers. Therefore, theoretically, there are 7,920,000 telephone numbers per area code.

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How many combinations of 3 numbers can you have without repetition?

There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.

How many combinations without repetition are possible if’n 5 and R 3?

10 possible combinations
And we input the number 5 for n, and 3 for r, and so we know that there 10 possible combinations.

How many 10-digit numbers can be made with odd digits so that no consecutive digits are same?

The ten digits numbers that can be made with odd digits so that no two consecutive digits are the same are 5 × 4`9. The odd digits which can be considered are (1,3,5,7 and 9).

How many digits are there in a phone number?

A phone number is composed of 10 digits. The first three are the area code the other 7 are the local telephone number which cannot begin with a 0. How many different telephone numbers are possible in a single area code? combinatorics Share Cite Follow edited Sep 6 ’14 at 18:33 user8028 asked Sep 6 ’14 at 0:30 user8028user8028

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How many possible phone numbers are there with 10 characters?

In your case the set of characters is the ten digits, so m = 10. The number of digits in the string is also ten, so n = 10. As a result the total number of possible phone “numbers” is 10 10 = 10 000 000 000 or ten billion (an eleven digit number).

How many possible permutations of a telephone number are there?

Number of different possible permutations of a telephone number. A telephone number consists of 10 digits, all from 0 to 9. The first digit is 0. The remaining digits can be any number ranging from 0 to 9.

How many possible numbers are there in 10^10?

If you have a three-digit phone number, the first and second digits have 100 possible values; for each of those the third digit has 10 possible values, giving 100*10 = 1000 possible numbers. So once we get to the 10th digit, we have 10^10 possible numbers. How much is 10^10? It’s 10’000’000’000, which many people refer to as 10 billion.