# How many four digits numbers can be formed using the digits 0 1 2 and 3 repetition is allowed )?

## How many four digits numbers can be formed using the digits 0 1 2 and 3 repetition is allowed )?

Therefore the number of four digit numbers formed using 0, 1, 2, 3 is 18.

## How many 4 digit odd numbers can be formed using the digits 0 1 2 and 3 only if the repetition of the digit is not allowed Brainly?

As stated in the title above: How many 4-digit odd numbers can be formed using the digits 0, 1, 2 and 3 only if the repetition of the digit is not allowed? I already have the answer for this and it is 8.

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How many four digit numbers can be constructed if zero Cannot be used for the first digit and digits may be repeated?

So, there are 4536, 4-digit numbers can be formed.

### How many four digit odd numbers can be formed using the digits?

Complete step-by-step answer: And the hundred’s also the same, 8 possible numbers, and coming to the ten’s place, we will have only 7 possible numbers to place in it. So the number of four-digit odd numbers can be formed is 2240.

### How many 4 digit numbers can be formed using the digits 0 7?

Answer is 840! This is a question of permutation and combination. We have to make 4 digit number without repetition using 1,2,3,4,5,6,7.

Can the digits of a 4 digit number be repeated?

However, the digits cannot be repeated In the 4 -digit numbers and thousands place is already occupied with a digit. The hundreds, tens, and units place is to be filled by the remaining 9 digits.

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#### How many 4-digit even numbers can you make with 4 numbers?

If the 4th digit is 0, then that leaves 5 possible numbers for the 1st digit, 4 for the 2nd, and 3 for the 3rd. 5 x 4 x 3 = 60 possible 4-digit even numbers. If the 4th digit is 2 or 6, that leaves 4 possible numbers for the 1st digit (can’t be 0), 4 for the 2nd digit, and 3 for the 3rd digit. 4 x 4 x 3 x 2 = 96 possible 4-digit even numbers.

#### How many 4 digit numbers can occupy the thousands place?

Since we have to find the number of 4 digit numbers, the first digit cannot take the value of 0. So not considering 0, we can have a total of 3 digits that can occupy the thousands place. As there is no repetition, the next place, i.e., the hundreds place can have any one of the 3 digits that are remaining.

How many 3 digit numbers are there with 9 different digits?

The hundreds, tens, and units place is to be filled by the remaining 9 digits. Therefore, there will be as many such 3 -digit numbers as there are permutations of 9 different digits taken 3 at a time.