How do you make a program reverse a number?

Let’s see a simple c example to reverse a given number.

1. #include
2. int main()
3. {
4. int n, reverse=0, rem;
5. printf(“Enter a number: “);
6. scanf(“\%d”, &n);
7. while(n!=0)
8. {

How do I print numbers in reverse order?

Write a program in C to display the number in reverse order.

1. Pictorial Presentation:
2. Sample Solution:
3. C Code: #include void main(){ int num,r,sum=0,t; printf(“Input a number: “); scanf(“\%d”,#); for(t=num;num!=0;num=num/10){ r=num \% 10; sum=sum*10+r; } printf(“The number in reverse order is : \%d \n”,sum); }

How do I print numbers backwards in C++?

Example: C++ Program to Reverse an Integer

1. In the first iteration of the loop, n = 12345. remainder 12345 \% 10 = 5. reversedNumber = 0 * 10 + 5 = 5.
2. In the second iteration of the loop, n = 1234. remainder 1234 \% 10 = 4. reversedNumber = 5 * 10 + 4 = 54.

How do you print a reverse number in Python?

Reverse Number In Python

1. # Python Program to Reverse a Number using While loop.
2. Number = int(input(“Please Enter any Number: “))
3. Reverse = 0.
4. while(Number > 0):
5. Reminder = Number .
6. Reverse = (Reverse *10) + Reminder.
7. Number = Number //10.
8. print(“\n Reverse of entered number is = \%d” \%Reverse)

How do you reverse and add a number until you get a palindrome in C?

C Program to Reverse a Number & Check if it is a Palindrome

1. Take the number which you have to reverse as the input.
2. Obtain its quotient and remainder.
3. Multiply the separate variable with 10 and add the obtained remainder to it.
4. Do step 2 again for the quotient and step 3 for the remainder obtained in step 4.

How do you print numbers in reverse order for loop?

Logic to print natural numbers in reverse

1. Input start limit from user. Store it in some variable say start .
2. Run a loop from start to 1 and decrement 1 in each iteration. The loop structure should look like for(i=start; i>=1; i–) .
3. Inside the loop body print the value of i .

How do you reverse a number recursion in C++?

Find reverse of a number using recursion

1. #include void reverse(int number) { if (number < 10) { printf(“\%d”,number);
2. #include void reverse(int number) { if (number < 10) {
3. public class ReverseNumberRecursion { public static void reverse(int number) { if (number < 10) { System.out.println(number);

How do you reverse a number in a for loop C++?

Cpp code to reverse a number using do-while loop

1. Declare and initialize two variables as int number,reversed_Num=0;
2. The user is asked to enter a number and it is stored in the integer variable of ‘number’
3. The do-while loop is used to find the reversed number of the given number.

How do you reverse a number in Python using built-in function?

Reverse a number in Python | Python Program to Reverse a number

1. INPUT FORMAT:
2. OUTPUT FORMAT:
3. SAMPLE INPUT: 321.
4. SAMPLE OUTPUT: 123.
5. Step 1:Get input from the user.
6. Step 3:Check whether the given number is greater than zero using while loop.
7. Step 5:Multiply rev by 10 and add the remainder to it, store the answer in rev.

How do you reverse a palindrome?

How do you reverse a list with a for loop?

We can use a for loop to swap the first and last items, the second and the one before the last item and so on until the list is reversed in place. The number of iterations needed is half the list size. If the list has an odd number of items then the middle item will stay in its place.

How to reverse the digits of an integer in JavaScript?

Write a program to reverse the digits of an integer. Time Complexity: O (log (n)), where n is the input number. Time Complexity: O (log (n)) where n is the input number. We will convert the number to a string using StringBuffer after this, we will reverse that string using the reverse () method

How do you get the reversed number of a number?

In each iteration, the remainder when the value of n is divided by 10 is calculated, reversedNumber is computed and the value of n is decreased 10 fold. Let us see this process in greater detail: And so on, until n == 0. Finally, the reversedNumber (which contains the reversed number) is printed on the screen.

Is there a way to represent an integer without a loop?

If you are willing to restrict yourself to machine integers, then can be done without a loop or recursion. In C++, this can be accomplished with the (ab)use of templates: // represent. Add one to get the // type can hold. If you are willing to restrict yourself to machine integers, then can be done without a loop or recursion.